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x^2-46x+360=0
a = 1; b = -46; c = +360;
Δ = b2-4ac
Δ = -462-4·1·360
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-26}{2*1}=\frac{20}{2} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+26}{2*1}=\frac{72}{2} =36 $
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